C(x)=X^2-4x+20

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Solution for C(x)=X^2-4x+20 equation: 



(C)=C^2-4C+20

We move all terms to the left:

(C)-(C^2-4C+20)=0

We get rid of parentheses

-C^2+C+4C-20=0

We add all the numbers together, and all the variables

-1C^2+5C-20=0

a = -1; b = 5; c = -20;
Δ = b2-4ac
Δ = 52-4·(-1)·(-20)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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